Web7 jul. 2024 · answered Jul 7, 2024 by Gavya (33.5k points) selected Jul 8, 2024 by Hailley Best answer Correct answer is (b) (a2 − b2) (a2 + b2) ( a 2 − b 2) ( a 2 + b 2) We have … WebIf (sin A/sin B)=m and (cos A/cos B)=n then find the value of tan B; n2 < 1 < m2. Q. If sinBsinA = m and cosBcosA = n then find the value of tanB; n2 < 1 < m2 . 4313 86 Trigonometric Functions Report Error A n2 B ± m2−11−n2 C n2/(m2 −1) D m2 Solution: Given, sinBsinA = m ⇒ sinA = msinB …(i) and cosBcosA = n ⇒ cosA = ncosB …(ii)
If tan A = n tan B and sin A = m sin B, then the value of cos2A is …
Web3 jan. 2024 · sin (A + B) = √3/2 and tan (A - B) = 1/√3 Concept Used: sin 60° = √3/2 tan 30° = 1/√3 Calculation: sin (A + B) = √3/2 as we know sin 60° = √3/2 (A + B) = 60 ---- (i) tan (A - B) = 1/√3 We know tan 30° = 1/√3 (A - B) = 30 ---- (ii) Add equation i and ii A = (60 + 30) / 2 A = 45° B = (60 - 30) / 2 B = 15° 2A + 3B = 90 + 45 = 135° Web4 jun. 2024 · Explanation: Since 0 < A < 90o we know that ∠A is in the first quadrant. Consider the right OAB where O is the origin and side AB is opposite ∠A We are told that sinA = 1 3 ∴ side AB = 1 and side OA = 3 Applying Pythagoras (OA)2 = (AB)2 + (OB)2 ∴ 32 = 12 + OB2 OB = √9 −1 [Since OB > 0 because ∠A is in the first quadrant] OB = √8 = 2√2 gary stephenson and snakes
Trigonometric Identities - math
WebIf tan A=n tan B and sin A = m sin B then show that cos²A=(m²-1)/(n²-1) ?L I K E C O M M E N T S H A I R S U B S C R I B E , ****. ... Web178 Likes, 13 Comments - Marisel Orozco Recetas sin remordimientos (@marisel.orozco) on Instagram: "BOLITAS ENERGÉTICAS DE CEREZA 朗 ( SIN GLUTEN, SIN AZÚCAR y VEGANAS ) . Ayer @avenayaguacat ... Web23 jul. 2016 · Prove tan ( A + B) using cos ( A − B) and sin ( A − B) Ask Question. Asked 6 years, 8 months ago. Modified 6 years, 8 months ago. Viewed 590 times. 2. Use cos ( A … gary stephenson spectrum